gold medal
Malik bought chargers that are shaped like regular octagons. If the chargers have the dimensions shown below, what is the area of one charger?
272 square inches 164 square inches 128 square inches 68 square inches
shown below? where? the posting must have been really below the screen :|
ahemm...=)
well... the Area of a Regular Polygon is \(\bf \cfrac{1}{2}\cdot apothem\cdot perimeter\)
is half 4?
but one of the 6in there, tells me it's not a regular octagon
of the total by adding all the numbers?
well, they want the Area, so you'd sum up all the Areas of the triangles and the rectangles in it, because the equations for a regular polygon, won't work because it not a regular polygon
do u add up all the numbers and then time by 4 which is half of 8?
well, I'd get the Area of the triangles and rectangles in it, and add them up
recall that the Area of a Triangle is \(\bf \cfrac{1}{2}\cdot base\cdot height\)
confusing me
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all 4 triangles in the shape, seem to have 4 for height and 4 for base
and what
and you'd use that to get their Area, \(\bf \cfrac{1}{2}\cdot base\cdot height\)
then you'd get the Area of the rectangles in the shape, and the sum all Areas up
and what is the answer
well... what did you for the Areas?
4*4 is and haft of 16
4*4 is 16
hmm 4*4 = 16
hmm what
done
hmmm \(\bf \cfrac{1}{\cancel{2}}\cdot \cancel{4}\cdot 4\implies 2\cdot 4\implies 8\)
so you have 4 of those triangles, so 8 * 4 = 32 so all 4 triangles area add up to 32 inches
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