Assume the height of females aged 20-29 years ols is normally distributed with a mean of 64.1 and a SD of 2.8 inches. Suppose a random sample of 4 girls is selected. What is the probability that all four will be 66 inches or taller?
what is your test statistic?
or better yet, do you have a ti83 by chance?
TI 89!
eww 89 eh, im not sure how much they changed it from the 83s
Im not sure. I can calculate the test statistic though.
is there a 2nd and a VARS bttons?
VARS-LINK
any thing that contains a normalCDF function?
the question is reading odd to me its either saying, find the probability of 66 and above and ^4 it or it is saying we modify the test statistic by sqrt(4) .... i originally thought the second, but the first is making more sense to me
This is the 3rd part of the question. In part a I found the probability of the whole population between 62 and 68 in. and in part b I found the probability that a random sample person will be 66 in or taller.
(66-64.1)/2.8 ... oh good, then you already have the 66 or taller
24.87% of picking a random person and getting 66 ir taller
yes I do. Do I raise that answer to 4?
if we pick 4 people then (true and true and true and true) is yeah, prob 66up raised to teh 4th
turns out to be .3%
.38% iswhat i see
yes sorry, i got that as well
cool
Thank you! and could I ask one more part?
sure
It reads "What is the distribution of the sample mean? Provide all characteristics"
did you take a sample beforehand? this might be easier to determine if you caould take a screenshot :/
ok I will get a picture of it!
by the central limit thrm, the mean of the sample means is normally distributed; but to ask how a single sample mean is distributed just reads bad
I figured that the answer was that it was normally distributed but it must be looking for more
pffftttt, yeah i got no idea what that is asking for :/ this might be useful tho: http://onlinestatbook.com/2/sampling_distributions/samp_dist_mean.html
Thanks! i'll take a look! I appreciate your help!
thats all i got for it :) good luck
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