Question

Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2).

y = -one thirdx - 6

y = -one thirdx - 14

y = 3x - 6

y = 3x - 14

Answer 1

3x-y=-3
-y=-3-3x
y=3+3x

parallel means the slope is the same.

Therefore, m=3
(4,-2)
Plug the values we have into y=mx+b
(-2)=(3)(4)+b
-2=12+b
b=-14
so... y=3x-14

Answer 2

thank you ! will you help on another ?

Answer 3

sure!

Answer 4

Write the equation of the line that is parallel to the line y = -3x + 12 and passes through the point (-1, 6).

y = one thirdx + 7

y = -3x + 3

y = one thirdx + 3

y = -3x + 7

Answer 5

ok so you do the same thing..
y=-3x+12
m=-3
(-1,6)
so... (6)=(-3)(-1)+b
6=3+b
b=3
and... y=-3x+3

Answer 6

thank you thank you so much! Last one ? lol

Answer 7

haha sure!

Answer 8

Write the equation of the line that is perpendicular to the line y = three halvesx + 4 and passes through the point (-6, 3).

y = three halvesx - 1

y = three halvesx + 3

y = -two thirdsx - 1

y = -two thirdsx + 3

Answer 9

ok so perpendicular slopes are the negative reciprical of the original slope. In this problem, the original slope is 3/2. Therefore the new slope or m is going to be -2/3.

so... m=-2/3
(-6,3)

(3)=(-2/3)(-6)+b
3=4+b
b=-1
so... y=-2/3x-1

Answer 10

Your the best! @kasper15

Answer 11

Thanks!