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Calculus1
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graph the equation by plotting 3 points 2y=-3x+2
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pick a value for "x", to get "y" lemme get the 1st point say x = 1, so 2y = -3x+2 => 2y = -3( 1 )+2 => 2y = -1 => \(y=-\cfrac{1}{2}\) now find the other 2 points
ohh the point would be of course... x = 1, \(y=-\cfrac{1}{2}\) so \(\left(1\quad ,\quad -\cfrac{1}{2}\right)\)
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