Question

Please help:

Limit of (x^3-4x)/(x^2-4) as x=2?

Answer 1

Have you studied L'Hopital's rule yet?

Answer 2

factor and cacel

Answer 3

Not really

Answer 4

\[\frac{ x^3 - 4x }{ x^2 - 4 } = \frac{ x(x^2 - 4) }{ x^2 - 4 } = x\]

Answer 5

ooop maybe "cancel"

Answer 6

Alright then follow @satellite73 and @Euler271 ...factor and cancel out

Answer 7

Thank you