Question

FOIL/SIMPLIFY h(x) = (x-2i)(x+2i)

Answer 1

I am just not sure how to FOIL with imaginary numbers and an x variable.

Answer 2

lets go step by step
xx+2xi+-2xi-4ii

Answer 3

So its \[x^{2} - 4i ^{2}\]

Answer 4

correct but what is i

Answer 5

-1?

Answer 6

\[(\sqrt{-1})^2 = -1\]

Answer 7

i is a square root of -1 so if we square it we get -1

Answer 8

now the equations is x^2 -4(-1)

Answer 9

x^2 + 4?

Answer 10

correct :D

Answer 11

Thank you! (:

Answer 12

np