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Mathematics 9 Online
OpenStudy (pixiedust1):

=

OpenStudy (pixiedust1):

@skullpatrol

OpenStudy (pixiedust1):

@Compassionate

OpenStudy (pixiedust1):

@jayz657

OpenStudy (pixiedust1):

@Loser66

OpenStudy (pixiedust1):

Hi guys! Mind helping me out?

OpenStudy (anonymous):

whats the question

OpenStudy (anonymous):

cant make any promises..have to see the question first

OpenStudy (pixiedust1):

I think it is B.

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

I agree :)

OpenStudy (anonymous):

i agree with you

OpenStudy (anonymous):

correct

OpenStudy (pixiedust1):

Thanks! Next one uses the graph. The relation between the top and bottom are 2n, correct?

OpenStudy (pixiedust1):

To be more specific... Which of the following rules represents the function shown in the table?

OpenStudy (anonymous):

I do not know that one...sorry...maybe jayz657 does

OpenStudy (pixiedust1):

That's fine :) This stuff is tough!!

OpenStudy (anonymous):

you want to have f(2) = 6, f(-1) = 3, f(0) = 0 so for some x when you plug in 2 it will come out 6 2 time some number will give you 6 same for the other ones

OpenStudy (anonymous):

sorry f(-1) = -3

OpenStudy (pixiedust1):

I think it is the s^2 (c)

OpenStudy (anonymous):

yea thats right but for the previous one, did you understand what i was saying i didnt give an answer yet

OpenStudy (pixiedust1):

Oh! And yes, I am with you so far :)

OpenStudy (anonymous):

alright then is there anything else you would like me to check?

OpenStudy (anonymous):

alright then i wait

OpenStudy (pixiedust1):

Thank you :)

OpenStudy (pixiedust1):

Okay, sorry for the wait

OpenStudy (pixiedust1):

Very sorry about that. But thank you for waiting :)

OpenStudy (anonymous):

all of them are correct

OpenStudy (pixiedust1):

REALLY???? WOW!!!!! THANK YOU THANK YOU THANK YOU!!

OpenStudy (pixiedust1):

How do I write a testimony? I wanna write one about you lol :D

OpenStudy (anonymous):

your welcome glad to help you can just write anything hahaha

OpenStudy (pixiedust1):

Okay! How would I write it? I'm new lol, not sure where to go to write it

OpenStudy (anonymous):

you have to fan jayz657 first

OpenStudy (anonymous):

hm.. actually im not sure i thought it was from the profile

OpenStudy (loser66):

I would like to write a testimonial to you. good student

OpenStudy (pixiedust1):

@jayz657 - I'll find a way lol @Loser66 - You would write one for me???????!! :D

OpenStudy (pixiedust1):

All I did was pester everyone for help :P

OpenStudy (anonymous):

i agree with loser, definitely a good student, keep at it :D

OpenStudy (loser66):

as a helper, I like a student who willing to study.

OpenStudy (anonymous):

your welcome thats a good mindset to have, keep at it, the hardwork definitely pays off in the end

OpenStudy (loser66):

pick jayz657 I follow him a while, he deserves it

OpenStudy (anonymous):

hehe alright you too :)

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