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OpenStudy (pixiedust1):
@skullpatrol
OpenStudy (pixiedust1):
@Compassionate
OpenStudy (pixiedust1):
@jayz657
OpenStudy (pixiedust1):
@Loser66
OpenStudy (pixiedust1):
Hi guys! Mind helping me out?
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OpenStudy (anonymous):
whats the question
OpenStudy (anonymous):
cant make any promises..have to see the question first
OpenStudy (pixiedust1):
I think it is B.
OpenStudy (anonymous):
correct
OpenStudy (anonymous):
I agree :)
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OpenStudy (anonymous):
i agree with you
OpenStudy (anonymous):
correct
OpenStudy (pixiedust1):
Thanks! Next one uses the graph.
The relation between the top and bottom are 2n, correct?
OpenStudy (pixiedust1):
To be more specific...
Which of the following rules represents the function shown in the table?
OpenStudy (anonymous):
I do not know that one...sorry...maybe jayz657 does
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OpenStudy (pixiedust1):
That's fine :)
This stuff is tough!!
OpenStudy (anonymous):
you want to have f(2) = 6, f(-1) = 3, f(0) = 0
so for some x when you plug in 2 it will come out 6
2 time some number will give you 6
same for the other ones
OpenStudy (anonymous):
sorry f(-1) = -3
OpenStudy (pixiedust1):
I think it is the s^2 (c)
OpenStudy (anonymous):
yea thats right
but for the previous one, did you understand what i was saying
i didnt give an answer yet
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OpenStudy (pixiedust1):
Oh! And yes, I am with you so far :)
OpenStudy (anonymous):
alright then is there anything else you would like me to check?
OpenStudy (anonymous):
alright then i wait
OpenStudy (pixiedust1):
Thank you :)
OpenStudy (pixiedust1):
Okay, sorry for the wait
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OpenStudy (pixiedust1):
Very sorry about that. But thank you for waiting :)
OpenStudy (anonymous):
all of them are correct
OpenStudy (pixiedust1):
REALLY???? WOW!!!!! THANK YOU THANK YOU THANK YOU!!
OpenStudy (pixiedust1):
How do I write a testimony? I wanna write one about you lol :D
OpenStudy (anonymous):
your welcome glad to help
you can just write anything hahaha
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OpenStudy (pixiedust1):
Okay! How would I write it?
I'm new lol, not sure where to go to write it
OpenStudy (anonymous):
you have to fan jayz657 first
OpenStudy (anonymous):
hm.. actually im not sure i thought it was from the profile
OpenStudy (loser66):
I would like to write a testimonial to you. good student
OpenStudy (pixiedust1):
@jayz657 - I'll find a way lol
@Loser66 - You would write one for me???????!! :D
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OpenStudy (pixiedust1):
All I did was pester everyone for help :P
OpenStudy (anonymous):
i agree with loser, definitely a good student, keep at it :D
OpenStudy (loser66):
as a helper, I like a student who willing to study.
OpenStudy (anonymous):
your welcome
thats a good mindset to have, keep at it, the hardwork definitely pays off in the end
OpenStudy (loser66):
pick jayz657 I follow him a while, he deserves it
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