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HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP :) The lengths of the sides of a triangle are 3x, 5x -12 and x + 20. Find the value of x so that the triangle is isoceles.
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just set two of the equations equal to each other and solve for x for example\[3x=x+10\]
So would i do 3x = x + 20?
get all your xs on one side \[3x=x+20\]\[-x = -x\]\[2x=20\] and what do you do next?
you divide 2x on each side and you get x = 10 right?
yes you got it
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okay that would be the answer?
yes by the way you wrote the question x=10 would be the answer
Lol that was simple thank you!
np
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