Question

closed

Answer 1

what is your problem

Answer 2

i need to graph this problem
a) state the y-intercept
b) determine the zeroes, to 1 decimal place (show your process)
c) use your results from a) and b), to clearly graph and label this quadratic relation
-y = -3x^2 - 7x + 8
y = -3(0) - 7(0) + 8
y = 8

y-intercept is at (0,8)

Find the zeroes, set y equal to zero.
y = -3x^2 - 7x + 8
0 = -3x^2 - 7x + 8

x = [-b±√(b²-4ac)] / 2a
a = -3, b = -7, c = 8

x = 7 ± √(49-4(-3)(8)) / 2*-3
x = 7 ± √(49+96) / -6
x = (7+√145)/-6 AND x = (7-√145)/-6

Answer 3

i have the answer i just need to graph