Write the slope-intercept equation of the line perpendicular to y = 5/2 x - 2, which passes though the point (0, 2).
Answer

y = 5x + 2

y = -2/5x + 2

y = 2x + 5

y = 1/2x + 5

Question

Write the slope-intercept equation of the line perpendicular to y = 5/2 x - 2, which passes though the point (0, 2).
Answer
		
y = 5x + 2
		
y = -2/5x + 2
		
y = 2x + 5
		
y = 1/2x + 5

anonymous · Answer

*dubstep

first find the slope of a line that is perpendicular to y = 5/2 x - 2. the slope of this line is 5/2, becuase it is the coefficient infront of the 'x'. to find a line perpendicular, we flip this fraction, so now it's 2/5 and we times it by a -1, so is now -2/5. this is the slope of a line that is perpendicular to the line  y = 5/2 x - 2 given.