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Mathematics 21 Online
OpenStudy (anonymous):

Solve: |x| < 2

OpenStudy (jdoe0001):

\(\bf |x|<2\implies \begin{cases} +(x)<2\\ \quad \\ \bf -(x)<2 \end{cases}\) so you'd have 2 values for "x", one for each scenario

OpenStudy (anonymous):

Thanks!

OpenStudy (jdoe0001):

yw

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