Question

Indeterminate Limits:
Evaluate 1-cos3x/8x^2 at x->0

Answer 1

I get how its in the indeterminate form of 0/0 but I'm not sure how my book is getting an answer of 0/0.

Answer 2

use L'hospital rule

Answer 3

For the derivative I get
\[\lim_{x \rightarrow 0}\frac{ 3\sin3x }{ 16x } \]
which gives me 0/0

Answer 4

derivative

Answer 5

it again

Answer 6

Oh I see, now i got it. Thanks

Answer 7

welcome