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Do you know how to factor x^2 + 10x + 9? Or x^2 + 4x - 45? if so, do that first
\[\frac{ x ^{2}+4x-45 }{ x ^{2}+10x+9 }\] Factor top and bottom \[\frac{ (x+9)(x-5) }{ (x+9)(x+1) }\] Cancel both (x+9) \[\frac{ x-5 }{ x+1 }\] To find the restrictions set (x+9) and (x+1) to 0 and solve for x \[x+9\neq 0 \] \[x \neq -9\] \[x+1 \neq 0\] \[x \neq -1\] So A
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