What is the solution set of this system of equations?

y = x^2 − 3x − 4
x = y + 8

A) {(-1,0), (4,0)}
B) {(8,0), (0,8)}
C) {(0,0)}
D) {(2,-6)}
E) No real solution

Question

What is the solution set of this system of equations?

y = x^2 − 3x − 4
x = y + 8 

A) {(-1,0), (4,0)}
B) {(8,0), (0,8)}
C) {(0,0)}
D) {(2,-6)}
E) No real solution

anonymous · Answer

The answer set is x = 2, y = -6. Refer to WolframAlpha here: http://www.wolframalpha.com/input/?i=y+%3D+x%5E2+-+3x+-4+and+y+%3D+x-8

anonymous · Answer

plug in x=y+8 in the first one

jdoe0001 · Answer

$\bf y = x^2 - 3x - 4\
x = y + 8 \ \quad \
0 = x^2 - 3x - 4\quad \textit{factor the equation to find "x"}$