Question

Factoring by grouping.. 7w^2+14w+wb+2b

How?

Answer 1

here is the first step
\[(7w^2+14w)+(wb+2b)\]
then pull a 7w out of the first one and a b out of the second one

Answer 2

you need to ull 7w out of the first oen. you want the final two factors in parenthesis to be equal

Answer 3

Answered previously to fast.. \[7w(w+2)+b(w+2) \to (7w+b)(w+2)\]

Answer 4

perfect

Answer 5

\[(7w ^{2}+14w)+(wb+2b)\]
Factor out common terms
\[7w(w+2) +b(w+2)\]
simplify
\[(7w+b)(w+2)\]

Answer 6

OH! I see now thank youuuuu that makes the rest of the problems oh so much easier.