Question

integrate: -0.5537e^-0.03767t

Answer 1

integrate: 7e^6t

Answer 2

\[\int ae^{bx}\,\mathrm dx=a\int e^{bx}\,\mathrm dx\\
\qquad\qquad=a\frac{e^{bx}}b+c\]


\[\int-0.5537e^{-0.03767t}\,\mathrm dt\\=-0.5537\int e^{-0.03767t}\,\mathrm dt\\=\]