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Mathematics 6 Online
OpenStudy (anonymous):

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hero (hero):

Oh there you are

OpenStudy (anonymous):

Oh, so its.. \[1 : 1\sqrt{2}\] ?

hero (hero):

Use the formula for Area of regular polygon to find the ratio

hero (hero):

Area of smaller polygon/Area of larger polygon

hero (hero):

\(A_{\text{poly}} = \dfrac{Pa}{2}\)

OpenStudy (anonymous):

since its pentagon.. shouldn't it be.. |dw:1385316731757:dw| ?

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