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Mathematics 22 Online
OpenStudy (anonymous):

For the function defined by function - http://i.imgur.com/QFYUAbp.png evaluate f(0) graph f(x)

OpenStudy (anonymous):

at x=0 the function is x^2 so what is f(0) ?

OpenStudy (sanjanap):

for f(0) just plug in 0

OpenStudy (ranga):

To graph f(x), for x <= 1, f(x) = x^2 (it is a parabola, for -infinity < x <= 1) for x > 1, f(x) = 2x + 1 ( it is a straight line for x > 1) |dw:1385350927245:dw|

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