Question

x^4-6x^2-27=0

Answer 1

x^4-6x^2-27=0
x^4-9x^2+3x^2-27=0
x^2(x^2-9)+3(x^2-9)=0
(x^2+3)(x^2-9)=0
(x^2+3)(x+3)(x-3)=0
Therefore,
x^2+3=0 or, x+3=0 or x-3=0
If x^2+3=0 ,then x^2= -3 or x=+-sqrt3i
If,x+3=0,then x= -3
If x-3=0,then x=3
x= +-sqrt3i,3 or -3

Answer 2

thankyou!

Answer 3

My Pleasure.

Answer 4

Can you help me with a couple more problems please?

Answer 5

i will try

Answer 6

I have the work for the problem.Polynomial with roots -3,6+i, but I have to describe my steps in words. Can you do that for me, cause I have no idea how I would put it in words.