Question

Solve the system.
2x+3y-2z=-5
-2x+2y+3z=6
x+y+z=2

Answer 1

easiest thing to do is eliminate x

add the 1st and 2nd equations and you get

2x + 3y - 2z = -5
-2x +2y +3z = 6
---------------------
5y + z = 1 equation 4


take the 3rd equation multiply it by -2 and add equation 1

2x + 3y -2z = -5
-2x -2y -2z = -4
----------------
y -4z = -9 Equation 5


make y the subject in equation 5 and substitute it into equation 4



y = -9 + 4z

so substituting
5(-9 + 4z) + z = 1

-45 + 20z + z = 1

just solve for z

then substitute into equation 4 to find y

then substitute into equation 1 to find x

all the answers involve fractions...

Answer 2

Ok. I got those. I didn't think I would have fractions. Thanks.

Answer 3

(1/21, -5/21, 46/21)