the point -3,2 and has a slope of three write this in point slope form slope intercept form and standard form plz help me
When you have a point (x1,y1) and slope (m) point slope form is y-y1=m(x-x1) so plug your point and slope into that
the slope would be m but where do i put the point at
for x1 and y1 (-3,2) ^ ^ x1 y1
so it would be y-2=3(x-3)
Close, gotta change the sign because plugging in the x we have y-2=3(x-(-3) two negatives make a positive y-2=3(x+3)
so thats your point slope form were done with that part
ok thanks man im just trying to ace a test im confused on can you help me with the other two forms
Yep, to get slope intercept form, just take point slope form and multiply out the right hand side and then isolate y
what would you multiply by
just multiply the parentheses y-2=3(x+3) y-2=3x+9 understand so far?
yeah then whats next after that
isolate y by adding 2 to both sides y=3x+11 and thats your slope intercept form
then how do you get the last form
Standard form looks like ax+by=c so we wanna get x and y on the left side in that order and the constant on the right subtract 3x from both sides -3x+y=11 looks good but sometimes they want the leading coefficient to be positive so we can make that happen my multiplying the entire equation by -1 3x-y=-11
so 3x-y=-11 is the standard form so it was that easy
yep
well thanks man i cant tell you how much of a help you were i really appreciate it
You're welcome
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