A particle is projected at an angle theta with initial velocity U. Its horizontal displacement(x) and height(y) are connected by this formula:

Y=XTan(Theta) - (gx^2)/(2U^2) Cos^2(Theta)

What is the maximum height to which the particle rise, and how far has it traveled horizontally?

Here's the answer the book provided:

(U^2)Sin^2(Theta)/2g ; (U^2)Sin^2(Theta)/2g

By the way, g is the acceleration due to gravity, so it's a constant.

Question

A particle is projected at an angle theta with initial velocity U. Its horizontal displacement(x) and height(y) are connected by this formula:

Y=XTan(Theta) - (gx^2)/(2U^2) Cos^2(Theta)

What is the maximum height to which the particle rise, and how far has it traveled horizontally?

Here's the answer the book provided:

(U^2)Sin^2(Theta)/2g ; (U^2)Sin^2(Theta)/2g

By the way, g is the acceleration due to gravity, so it's a constant.

anonymous · Answer

By the way, I'm curious as to how to solve this problem, in case anyone is wondering why I gave the answer.