Question

Help asap please?

A plane flies due north (90° from east) with a velocity of 100 km/h for 3 hours. During this time, a steady wind blows southeast at 30 km/h at an angle of 315° from due east. After 3 hours, where will the plane’s position be relative to its starting point? Show your work.

Answer 1

Use summation of vectors:

My steps:
(1) draw an initial sketch
(2) solve for the horizontal and vertical components of each initial vector
(3) add the respective components to get the components of the resultant vector
(4) scale the resultant vector components by 3 for the 3 hours
(5) solve for the resultant vector magnitude using pythagorean theorem
(6) solve the angle of the resultant vector with simple trigonometry

Result: plane is 244.55 km away @ 74.81 degrees North of East

Hope this helps out!