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Mathematics 6 Online
OpenStudy (anonymous):

y^3 - 14y^2 + 45y factor completely

OpenStudy (anonymous):

well the constant is zero.

OpenStudy (nikato):

It's factorable. What do all three terms have in common?

OpenStudy (anonymous):

have to pull a y out

OpenStudy (anonymous):

how do you work out the solution

OpenStudy (anonymous):

factor a y out of the statement and you get y(sadlfksdjf;lj) as a quadratic factor that will factor further into linear factors once you get a constant (number without a variable coefficient)

OpenStudy (nikato):

Once u factor a y out, u get y(y^2-14y+45) Do u know how to factor what's in the parantheses?

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