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find the integral from -1 to 1 of √1+x dx
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integral by u-sub u = 1+x
How do you get the 2/3?
hey, thats wrong. dont listen to zeph
That's wrong
my bad
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did you try the u = 1+x by yourself first ?
\[\int\limits_{-1}^{1}\sqrt{1+x} \mathrm d x\] Let u=x+1, then du=dx Find new limits of integration\[=\int\limits \sqrt{u} \mathrm d u\]
remember square root is an exponent of 1/2
Am I wrong? @Xeph
i'm not sure, i got|dw:1385341931533:dw|
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