$$\frac{-5 + i}{2i}$$
$$\frac{-5 + i}{2i} \times (2i)$$
$$-10i + 2i^2$$
$$-10i + 2i^2 \times 2(-1)$$
$$-10 \sqrt(-1) - 2$$
My answer:
$$-10 \sqrt{-1} - 2$$
Computers answer:
http://www.wolframalpha.com/input/?i=%28-5+%2B+i%29%2F2i

What am I doing wrong? (I just learned about imaginary numbers so it might be some stupid mistakes, please help.)

Question

$$\frac{-5 + i}{2i}$$
$$\frac{-5 + i}{2i} \times (2i)$$
$$-10i + 2i^2$$
$$-10i + 2i^2 \times 2(-1)$$
$$-10 \sqrt(-1) - 2$$
My answer:
$$-10 \sqrt{-1} - 2$$
Computers answer:
http://www.wolframalpha.com/input/?i=%28-5+%2B+i%29%2F2i

What am I doing wrong? (I just learned about imaginary numbers so it might be some stupid mistakes, please help.)

charlotte123 · Answer

Never heard of imaginary numbers before LOL

anonymous · Answer

I see. You just multiplied by a (2i) from nowhere. Multiply it by (2i)/(2i)

bibby · Answer

It's also worth noting that the equation you put into wolfram was being read like this

anonymous · Answer

|dw:1385347563533:dw|
I did that?

anonymous · Answer

@bibby oh so is my version right?

bibby · Answer

I'm not sure and don't really want to do math right now lol. http://www.wolframalpha.com/input/?i=%28-5+%2B+i%29%2F%282i%29 wolfram says$$1/2 + 5i/2$$

bibby · Answer

eh, I'll try it out|dw:1385347851640:dw|