Question

Write the coordinate point for the vertex of this parabola: x=-1/8y^2.

Answer 1

This is a sideways parabola.
The vertex form of a sideways parabola is: x = a(y - k)^2 + h where (h,k) is the vertex.
Compare x = -1/8y^2 to the vertex form and you can see a = -1/8, h = 0, k = 0
Therefore, the vertex is (0,0) (the origin)
a is negative and therefore the parabola opens up in the negative x direction.

Answer 2

thank you :)