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OpenStudy (anonymous):
-4+log5(x-2)=-3
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OpenStudy (kirbykirby):
is that \(\text{log}_5(x-2)\)
OpenStudy (anonymous):
oh yes
OpenStudy (kirbykirby):
\(\log_5(x-2)=-3+4\\ \log_5(x-2)=1\\ 5^1=(x-2)\\ 5=x-2\\ x=7\)
OpenStudy (anonymous):
thank you
OpenStudy (kirbykirby):
:)
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