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solve 2x^2=4x+6
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first I would dived all by two to get rid of some numbers. Then you should get it equal to zero and factor the result
so 2x^2 -4x-6
=0
so the 2 would go away
now you have x^-2x-3=0
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factor this
x^2 sorry
(x-2) (x-1)
close but -1 X-2 =2 not -3
2x^2-4x-6 x^2 - 2x-3 complete the square so x^2-2x+1=3+1 (x-1)^2+4 x=1+/-root4 which is 2 x= 1+2 or 1-2 x= 3 or x= -1
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That way works but it is easier when you factor instead of completing the square
did you get the factors? @michcard
yes
good
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