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Mathematics 18 Online
OpenStudy (anonymous):

solve 2x^2=4x+6

OpenStudy (anonymous):

first I would dived all by two to get rid of some numbers. Then you should get it equal to zero and factor the result

OpenStudy (anonymous):

so 2x^2 -4x-6

OpenStudy (anonymous):

=0

OpenStudy (anonymous):

so the 2 would go away

OpenStudy (anonymous):

now you have x^-2x-3=0

OpenStudy (anonymous):

factor this

OpenStudy (anonymous):

x^2 sorry

OpenStudy (anonymous):

(x-2) (x-1)

OpenStudy (anonymous):

close but -1 X-2 =2 not -3

OpenStudy (anonymous):

2x^2-4x-6 x^2 - 2x-3 complete the square so x^2-2x+1=3+1 (x-1)^2+4 x=1+/-root4 which is 2 x= 1+2 or 1-2 x= 3 or x= -1

OpenStudy (anonymous):

That way works but it is easier when you factor instead of completing the square

OpenStudy (anonymous):

did you get the factors? @michcard

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

good

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