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find the area of the triangle.
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A=1/2*b*h
|dw:1385426216774:dw| do i simple use the formula \[area of \triangle = (\frac{ 1 }{ 2 })(b)(h)\] \[= (\frac{ 1 }{ 2 })(20)(44)\] \[=440\] or still have to use the sin/cosin law/etc?
what u have is correct what else are you looking for
oh, okay, just makng sure, thanks:)
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