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csc^2-4=0
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csc^2=4
solve it now take sqrt both side
yes, and then take the inverse cosine of what you get.
\[\csc^2x-4=0\]
\[add~~4~~t o~~both~~sides,~~~~~~\csc^2x=4\]\[take~~a~~squ are~~r oot~~o f~~both~~sides,~~~~~~~cscx=2\]\[\csc ^{-1}(2),~~~~~~(or~~\sin ^{-1}(1/2))~~~~is?\]
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30?
careful here
\[\csc^2(x)=4\\ \csc(x)=2,\csc(x)=-2\\ \sin(x)=\frac{1}{2},\sin(x)=-\frac{1}{2}\]
oh, yeah, forgot about the plus minus, ty, satelline...
it would be\[either~~~Sin ^{-1}(1/2)~~~or~~~~~~Sin ^{-1}(-1/2)\]
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\[\cos^2x+2\cos x=3\]
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