Question

3+ log base 5 (-5x)=4

Answer 1

First add 3 to both sides

Answer 2

3+log base5 (-5x)=7 ?

Answer 3

yep but the three is gone now so you have

log_5(-5x)=7

apply base 5 exponential to both sides...

\[5^{\log _{5}-5x}=5^7\]

log and base 5 cancels

-5x=5^7

should be easy now

Answer 4

thank you

Answer 5

You're welcome