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what is an equation of the line that passes through the points (-4,3) and (-1,6) A. y=-x-7 B. y=-x-1 C. y=7x+1 D. y=x+7
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do you know how to find the slope ?
is it the y2-y1 thing ?
slope(m) = (y2 - y1) / (x2 - x1) (-4,3) x1 = -4 and y1 = 3 (-1,6) x2 = -1 and y2 = 6 now we sub slope(m) = (6 - 3) / (-1 - (-4) m = 3/(-1 + 4) m = 3/3 m = 1 <-- your slope understand me so far ?
yes :)
which answer choice is it ?
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now we can use y = mx + b, because we know the slope is 1 and we need to find the y intercept, which is b. y = mx + b m = 1 (-1,6) x = -1 and y = 6 sub y = mx + b 6 = 1(-1) + b 6 = -1 + b 6 + 1 = b 7 = b making your equation : y = x + 7
.thank you so much
no problem :)
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