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OpenStudy (anonymous):
Solve.
–6 ≥ 10 – 8x
A.
x ≤ 2
B.
x ≥ –2
C.
x ≤ –2
D.
x ≥ 2
OpenStudy (anonymous):
add 8 to both sides
OpenStudy (anonymous):
sorry i mean 8x to both sides
OpenStudy (anonymous):
8x-6>_10
OpenStudy (anonymous):
plus 6 both sides
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OpenStudy (anonymous):
8x>_ 10 +6
OpenStudy (anonymous):
divide by 8
OpenStudy (anonymous):
x = 2
OpenStudy (anonymous):
x >_ 2
OpenStudy (anonymous):
i did that but i got 4 um greater than x.
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OpenStudy (anonymous):
no, 10/8 = 1.25 and 6/8 = .75
OpenStudy (anonymous):
that gives you 2
OpenStudy (anonymous):
i still dont get it sorry
OpenStudy (anonymous):
no i get it thanks
OpenStudy (anonymous):
can you help me on one more
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OpenStudy (anonymous):
–6 ≥ 10 – 8x
+8x + 8x
8x - 6 ≥ 10
+ 6 + 6
8x ≥ 10 +6
(you can do two things here. what I did was a little more complicated maybe its why you didnt understand.)
8x ≥ 16 (add the number)
x≥ 2 (divide by 8 both sides)
OR
OpenStudy (anonymous):
now i get it
OpenStudy (anonymous):
8x ≥ 10 +6
x ≥ 1.75 + .75
(divide each number seperately by 8 )
x ≥ 2
then add
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
:)
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OpenStudy (anonymous):
can you help me on one more
OpenStudy (anonymous):
Solve.
3 + d < 3 – d
A.
d < –6
B.
d < 0
C.
d > –3
D.
d < 6
OpenStudy (anonymous):
3 + d < 3 – d
+d + d
3+d+d < 3
3 + d^2 <3
-3 -3
d^2<3-3
d^2< 0
sqrt d^2 < sqrt 0
d<0