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Mathematics 8 Online
OpenStudy (anonymous):

help fan and medal!!!

OpenStudy (anonymous):

Solve. –6 ≥ 10 – 8x A. x ≤ 2 B. x ≥ –2 C. x ≤ –2 D. x ≥ 2

OpenStudy (anonymous):

add 8 to both sides

OpenStudy (anonymous):

sorry i mean 8x to both sides

OpenStudy (anonymous):

8x-6>_10

OpenStudy (anonymous):

plus 6 both sides

OpenStudy (anonymous):

8x>_ 10 +6

OpenStudy (anonymous):

divide by 8

OpenStudy (anonymous):

x = 2

OpenStudy (anonymous):

x >_ 2

OpenStudy (anonymous):

i did that but i got 4 um greater than x.

OpenStudy (anonymous):

no, 10/8 = 1.25 and 6/8 = .75

OpenStudy (anonymous):

that gives you 2

OpenStudy (anonymous):

i still dont get it sorry

OpenStudy (anonymous):

no i get it thanks

OpenStudy (anonymous):

can you help me on one more

OpenStudy (anonymous):

–6 ≥ 10 – 8x +8x + 8x 8x - 6 ≥ 10 + 6 + 6 8x ≥ 10 +6 (you can do two things here. what I did was a little more complicated maybe its why you didnt understand.) 8x ≥ 16 (add the number) x≥ 2 (divide by 8 both sides) OR

OpenStudy (anonymous):

now i get it

OpenStudy (anonymous):

8x ≥ 10 +6 x ≥ 1.75 + .75 (divide each number seperately by 8 ) x ≥ 2 then add

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

can you help me on one more

OpenStudy (anonymous):

Solve. 3 + d < 3 – d A. d < –6 B. d < 0 C. d > –3 D. d < 6

OpenStudy (anonymous):

3 + d < 3 – d +d + d 3+d+d < 3 3 + d^2 <3 -3 -3 d^2<3-3 d^2< 0 sqrt d^2 < sqrt 0 d<0

OpenStudy (anonymous):

hay thanks a million!!! :)))))

OpenStudy (anonymous):

no problem :)

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