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What is the axis of symmetry for f(x) = −5x2 − 20x − 10? x = 6 x = −6 x = 2 x = −2
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the axis of symmetry of a parabola \[y = ax^2 + bx + c\] is found using \[x = \frac{-b}{2a}\] in your question b = -20 and a = -5 just substitute and evaluate
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