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Verify that quadrilateral BCDE is a rhombus with vertices B(-5, 1), C(0, 6), D(5, 1) and E (0, -4) by showing that all four sides are equal. A. BD = CE = Square root of 50 B. BD = CE = 50 C. BC = CD = DE = EB = 50 D. BC = CD = DE = EB = Square root of 50
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check the length of all segments, that is, from one point to the other, that is, from B to C and C to D and D to E and E to B use the distance formula \(\large{ \textit{distance between 2 points}\\ \quad \\ d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}}\)
okay thanks
yw
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