Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bars sell for $5 per pound and the milk chocolate fudge bars sell for $4 per pound. You purchased a combination of these bars for your family and friends and your bill came to $150. This scenario can be modeled by the equation 5d + 4m = 150. Which of the following is not a possible combination of dark chocolate fudge bars and milk chocolate fudge bars?

6 dark bars and 30 milk bars
10 dark bars and 25 milk bars
12 dark bars and 23 milk bars
14 dark bars and 20 milk bars

Question

Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bars sell for $5 per pound and the milk chocolate fudge bars sell for $4 per pound. You purchased a combination of these bars for your family and friends and your bill came to $150. This scenario can be modeled by the equation 5d + 4m = 150. Which of the following is not a possible combination of dark chocolate fudge bars and milk chocolate fudge bars?
 	
	6 dark bars and 30 milk bars
	10 dark bars and 25 milk bars
	12 dark bars and 23 milk bars
	14 dark bars and 20 milk bars

studygurl14 · Answer

6 dark bars and 30 milk bars --> 6(5) + 30(4) --> 30 + 120  --> $150 
This is a possible scenario, so you can eliminate the first one
Just keep doing that until you find one that DOESN'T equal $150

anonymous · Answer

Thanks a ton! I got 12 dark and 23 milk. Thats correct, right? :)  @StudyGurl14

studygurl14 · Answer

Great job! You got it!