On a map, 1 in. represents 20 mi. Two cities are in. apart on the map. How far apart are the actual cities? A.23 1/2 mi B.60 1/2mi C.70 mi D.75mi please help!!
"Two cities are in. apart on the map." ^ ?
what is the missing thing ? its hard to solve with no given
3and 1/2 sorry
sooo do any of you know?
\(\bf \begin{array}{llll} \textit{map inches}&\textit{actual miles}\\ 1&20\\ x&3\frac{1}{2} \end{array}\implies \cfrac{1}{x}=\cfrac{20}{3\frac{1}{2}}\)
solve for "x"
i do not know the answer?!
hmmmm shoot I got the wrong... ... one sec... the wrong item in the wrong column =)
\(\bf \begin{array}{llll} \textit{map inches}&\textit{actual miles}\\ 1&20\\ 3\frac{1}{2}&x \end{array}\implies \cfrac{1}{3\frac{1}{2}}=\cfrac{20}{x}\)
now just solve for "x", tis a plain linear equation simplification
we cannot give out the answer however we can help you get it and understand it @jdoe0001 gave you a great way to start and a good format its not so hard man
the answer is 70 correct
how did you get 70?
i am a girl!!!
\(\Large ?\)
girl*
i did 3 1/2 broke it into a decimal and then i multiplyed 3.5 times 20 easy and it is correct right?
bye and thank you guys soo much!!
hehehyes,it's 70 =)
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