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Mathematics 22 Online
OpenStudy (anonymous):

2sin^2x+3cosx=0

OpenStudy (anonymous):

What's the question?

OpenStudy (anonymous):

Im guessing its find the exact values

OpenStudy (anonymous):

Use identity cos^2(x) + sin^2(x) = 1 to change the sin^2(x) into a cosx term

OpenStudy (anonymous):

expand, let a = cosx... factor, sub a = cosx back and solve using your unit circle or special triangles

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