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OpenStudy (anonymous):
2sin^2x+3cosx=0
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OpenStudy (anonymous):
What's the question?
OpenStudy (anonymous):
Im guessing its find the exact values
OpenStudy (anonymous):
Use identity cos^2(x) + sin^2(x) = 1 to change the sin^2(x) into a cosx term
OpenStudy (anonymous):
expand, let a = cosx... factor, sub a = cosx back and solve using your unit circle or special triangles
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