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How do you simplify B= log (I/ 10^-16) ?
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hint : 1/10^-6 = 10^6
Umm, okay im gonna change I to x so B= log ( x/ 10^-16) would it be log x - log 10 ^ -16 ?
no, that should be log x + log 10^6 remmber that : log (a * b) = log a + log b
but...... its log (x DIVIDED BY 10^-16)
\[\log \frac{ x }{ 10^{-16} }\]
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so it'd be subtraction npt addition
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