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Help!! 2^x=.4 how to solve without a calc
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well you square both sides which cancels out the x and you get X=2
ooops very sorry i wrote it wrong 2^x=.4
oh haha
okay! gimme a sec.
okay :p
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since you cant make the base = you have to use log
but in class i learned only how to solve without calculator, and i will learn it in the next sections, may I know how to do that thanks
take this problem \[7^x=12\] \[\ln 7^x=\ln 12\] \[x \ln 7= \ln 12\] \[x=\frac{ \ln 12 }{ \ln 7 }\] \[\approx 1.277\] this is straight out of my algebra book.
thank you very much
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