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What are the real or imaginary solutions of the polynomial equation?
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x^4 - 41x^2 = -400
first write it as x^4 -41x^2 +400 = 0 if you let y=x^2, you can say y^2 -41y +400 =0 do you know how to use the quadratic formula to find y ? once you find the two values of y, x = ±sqrt(y)
The quadratic formula. \[\huge x = \frac{ -b \pm \sqrt{b^2-4(a)(c)} }{ 2(a) }\] Your values of a, b, and c are found from looking at this ax^2 + bx + c = 0 For this equation a = 1 , b= -41 , c = 400
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