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If an elevator with mass M falls down a shaft onto a spring, from height h, find value of spring constant k so that max acceleration on elevator is no more than 5 g
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Ive gotten pretty far and have thesolution but theres one part I just dont understand...
what is the formula to find the constant k?
tell me what you know
1/2mv^2 sub 1 +mgysub1 +1/2kx^2 sub1= 1/2mv^2 sub 2 + mgysub2 + 1/2kx^2 sub 2
let me write this down on paper
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intial velocity mv^2 sub 1 equals 0, 1/2kx^2 sub 1 equals 0, mv^2 sub 2 equals zero and mg y sub 2 equals zero
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