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OpenStudy (anonymous):
Solve 2sinx-√ 3=0....... My test is tomorrow and I don't remeber how to do this.. Please guys help me :(!!!
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hero (hero):
\[2\sin(x) - \sqrt{3} = 0\]
hero (hero):
Add \(\sqrt{3}\) to both sides to get:
\[2\sin(x) = \sqrt{3}\]
OpenStudy (anonymous):
then divide by 2
OpenStudy (anonymous):
see the answer now?
hero (hero):
Divide both sides by 2 to get:
\[\sin(x) = \frac{\sqrt{3}}{2}\]
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hero (hero):
Take inverse sine of both sides to isolate \(x\)
OpenStudy (anonymous):
any other questions?
OpenStudy (anonymous):
inverse sin (sqrt(3)/2)
OpenStudy (anonymous):
inverse sin (2) is an error because sin is always between 1 and -1
OpenStudy (anonymous):
sqrt ?? so how I solve this problem :(
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OpenStudy (anonymous):
what kind of calculator do you have?
OpenStudy (anonymous):
SHARP advanced D.A.L. (EL-520X)
OpenStudy (anonymous):
does it show inverse trigonometry operations as "sin^(-1)" or as "arcsin"
OpenStudy (anonymous):
sin^-1
OpenStudy (anonymous):
but its the same thing.. the question is, how I do it if its an error for the calculator
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hero (hero):
Get a TI-Nspire quick. Throw that Sharp calc in the trash.
OpenStudy (anonymous):
sin^(-1) ((sqrt(3))/2)
OpenStudy (anonymous):
what is sqrt :(
OpenStudy (anonymous):
square root
sorry
OpenStudy (anonymous):
|dw:1385445765403:dw|
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