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is it the same as the last one? i answered it there completely
Evaluate sin(arccos(-9/sqrt(145)) a. 8/sqrt(145) b. -sqrt(145)/sqrt(248) c. sqrt(145)/sqrt(248) d. -8/sqrt(145)
@satellite73 thank you!!!!!!!!!!!!!! :)
third side is \(\sqrt{\sqrt{145}^2-9^2}=\sqrt{154-81}=\sqrt{64}=8\)
answer is \(\frac{8}{\sqrt{145}}\)
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yw
thank you so so so much!!!!!!!!!!!!!! :)
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