Question

Solve the exponential equation 3^x^2+5x=1/81

Answer 1

\[3^{x ^{2}+5x}=\frac{ 1 }{81 }=\frac{ 1 }{3^{4} }=3^{-4}\]
\[x ^{2}+5x+4=0\]
make factors and find the values of x

Answer 2

(x-5)(x+1)
x=5
x=-1

Answer 3

wrong.

Answer 4

\[(x+1)(x+4)=0~~~~~~~~~~~~~~~~~~~~~~~~x=-1,~~~~~~x=-4\]