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solve the logarithmic equation log(x+3)+logx=1
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\[\log \left( x+3 \right)+logx=1,\] \[logx \left( x+3 \right)=1=\log10\] \[x \left( x+3 \right)=10\] \[x ^{2}+3x-10=0\] make factors and solve for x.
-5,2
x=-5 rejected because domain of log is (0,infinity)
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