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Solve the logarithmic equation log(5+x)-log(x-2)=log2
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\[\log _{a}x-\log _{a}y=\log _{a}x/y\] applying that here... log((5+x)/(x-2))=log 2 since log is being taken of both sides you can just equate the two (5+x)/(x-2)=2 know what to do from here?
no
Multiply sides by x-2 5+x=2(x-2) 5+x=2x-4 9+x=2x 9=x
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