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Find the exact value given the following cos theta =2/9 and theta in quadrant IV find sin theta Help plzzzz
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\[\sqrt{c ^2-a^2}=b\]
\[\sqrt{2^2-9^2}=\]
\[\sqrt{4-81}= 8.02\]
right
Depends on if you're teacher wants it in decimal form or not. Since it says exact value its probably best to leave it as \[\sqrt{77}\]
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Oh and, since it's in quadrant 4, and we are looking for the y value, it's negative
|dw:1385503096839:dw|
http://openstudy.com/updates/529511f4e4b01081cd1eb935 http://openstudy.com/updates/52950e14e4b01081cd1eb6a2 http://openstudy.com/updates/52950c60e4b01081cd1eb59b
Sin = opposite/hypotenuse So sin = \[\frac{ -\sqrt{77} }{ 9 }\]
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