Question

In the below system, solve for y in the first equation.
x + 3y = 6
2x - y = 10

Answer 1

solve for y just in the first equation ? Not in the system of equations ?

Answer 2

yeah thats what it is asking

Answer 3

x + 3y = 6
3y = -x + 6
y = (-x + 6)/3 or y = -1/3x + 2

Answer 4

Solve 7x - 2y = -3
14x + y = 14
so here i add the like terms?

Answer 5

7x+13x?

Answer 6

what are you trying to find ?

Answer 7

Is it the same as the first?

Answer 8

it just says solve

Answer 9

Solve
7x - 2y = -3
14x + y = 14

Answer 10

substitution or elimination ?

Answer 11

which one is better?

Answer 12

substitution is easier...we will do that.
14x + y = 14 (we need to isolate a variable)
y = -14x + 14

now we sub -14x + 14 in for y in the other equation
7x - 2y = -3
7x - 2(-14x + 14) = -3 (distribute through the parenthesis)
7x + 28x - 28 = -3 (add 28 to both sides)
7x + 28x = -3 + 28 (combine like terms)
35x = 25
x = 25/35
x = 5/7

now we sub 5/7 in for x
y = -14x + 14
y = -14(5/7) + 14
y = - 70/7 + 14
y = - 10 + 14
y = 4

check..
7x - 2y = -3
7(5/7) - 2(4) = -3
35/7 - 8 = -3
5 - 8 = -3
-3 = -3 (correct)

x = 5/7 and y = 4

Answer 13

do you have any questions at all ?

Answer 14

no i got every step, thank you..

Answer 15

your very welcome :)

Answer 16

can you help me with another one?

Answer 17

sure...what you got ?